Load Q = +0.00000002 C is fixed in the horizontal plane position A. Another particle of mass m = 0.000001 kg and charge q = +0.000004 C is released from position B with AB 
= r = 2 m and moves due to its interaction with Q in the smooth horizontal plane.
It is given that:
AG = r = 2.5 m.
After point C, q enters perpendicular to the dynamic lines of a homogeneous electric field of intensity E = 100 V/m and length L = 12 cm created by parallel horizontal capacitor armatures spaced d . The charge q enters at the midpoint of the armature spacing d and at the moment q enters the homogeneous field, Q is moved away so that the charges do not interact. Consider the gravitational field negligible and calculate : Δ1. The velocity of the charge q at position C
Δ2. The time it will take the charge q to cross the homogeneous electric field,
Δ3. The armature distance d, if q exits tangentially from the edge of the bottom armature of the capacitor .
D4 The velocity at which q exits the field
Δ5. The potential difference between the charge input/output points
q from the electric field .
Δ6. The change in momentum between the points of entry and exit of charge q from the electric field .

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