Which rule must be used to find the number of strings of four decimal digits that do not contain the same digit twice?

Question

Which rule must be used to find the number of strings of four decimal digits that do not contain the same digit twice?






The division rule





The sum rule





The subtraction rule





The product rule

laradd · Answer

The product rule
 
Heres an example:How many strings of 4 decimal digits that do not contain the same digit twice.
We want to chose a digit, then another that is not the same, then another
First digit: 10 possibilities &bull; Second digit: 9 possibilities (all but first digit) &bull; Third digit: 8 possibilities &bull; Fourth digit: 7 possibilities
Total = 10*9*8*7 = 5040

ya3r · Answer

If you can ,use repetitive digits, then it can be calculated this : O x O x O x O = | | | | | | | \==> It has 10 condition! | | \ ==> It has 10 condition! | \ ==> It has 10 condition too. \==> It has 9 condition (zero cantt be there!) the total condition was calculated by multiple rule and it has 9,000 different condition!
 
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jasmine23 · Answer

It is definately the product rule

bhanuteja · Answer

The product rule 
We choose a digit, then another that is not the same,
&bull; First digit: 10 possibilities Second digit: 9 possibilities (all but first digit) 4
&bull; Second digit: 9 possibilities (all but first digit) 
&bull; Third digit: 8 possibilities
&bull; Fourth digit: 7 possibilities Total = 10*9*8*7 = 5040

medlifecrisis · Answer

The product rule can be used to answer your question. 
 
The reason is this:
- Each digit contains a possibility of choices (0-9). That is 10 options, therefore
- Digit 1 = 10 possibilities 
- Digit 2 = 9 possibilities (cannot be the same as the one before it, therefore it is 9 instead of 10) 
- Digit 3 = 8 possbilities 
- Digit 4 = 7 possibilities
Total = 10*9*8*7 = 5040 (number of strings of 4 decimal digits that do not contain the same digit twice)

megmegino · Answer

The answer is the product rule:
How many strings of four decimal digits do not contain the same digit twice?...
First digit: 10 possibilities,  Second digit: 9 possibilities, third digit: 8 possibilities, Fourth digit: 7 possibilities 
Therefore the answer will be 10*9*8*7 which will be 5040 possibilities

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Which rule must be used to find the number of strings of four decimal digits that do not contain the same digit twice?

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