Network Technology

Question

two stations working with the ethernet 10 mbp half duplex protocol are separated by the link
shown in the figure. calculate the allowable length of the second fragment so that the trans-
mitting system can detect the collision. give the result in meters, rounding to the nearest
whole number

vip308 · Answer

consider the above situation: two stations, a & b and the mid-point, p. let the unknown distance (pb) be ‘d’ kilometres. it is given that, propagation time, t_p = (1.5/200000) s + (d/250000) s we know that, size of the packet = 4 bytes bandwidth of the link = 10 mb/s (time taken = distance/speed; total time, t_p = t₁+t₂) or, t_p = (375000+200000d)/(50000000000) or, t_p = (375+200d)/(50000000) or, t_p = (15+4d)/(2000000) size of the packet >= 2 * t_p * bandwidth of the link or, 4 b >= 2 * ((15+4d)/2000000) s * 10 mb/s or, 4 b >= ((15+4d)/1000000) s * 10^6 b/s or, 4d + 15 <= 4 or, d <= 11/4 or, d <= 2.75 therefore, allowable length = 2750 m

boluo · Answer

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