Do not forget to add 5 stars ratings as you know this is my real reward of all hard working.Please find attachment. Read this well and use it to enhance as well as develop your understanding and knowledge about the given assignment. If you have any queries feel free to send me a message. Thank you very much! BEST OF LUCK :) regards,Dr. Charles Kennedy (expertsolution) Answer Q1 Answer Q 2 Answer Q2: Loop: slt $t2, $0, $t1 ;Let the address location of loop be 0x1234 0x0009502A beq $t2, $0, done ;Let the address location of done be 0x0x1239 0x11401239 subi $t1,$t1,1 ;Subi (Subtract Immediate) instruction is not available in the MIPS assembly language, The same operation can be carried out by the ADDI(Add Immediate) instruction since the negative number is added with its 2’s compliment representation, 0x21290001 addi $s2, $s2,2 ; 0x22520002 j loop ; 0x08001234 Done: ;Let this address location be 0x1239 Answer Q4: Given that MIPS sw $t1 32($t2) to HEXADECIMAL SW => 100011 base => $t2 => 01010 rt => $t1 => 01001 offset => 32 => 0000000000100000 Now, convert 100011 01010 01001 0000000000100000 to hexadecimal (By Use table to convert from binary to hexadecimal) we get, 0x8D490020 NOTE : By using binary to hexadecimal table: 1000 => 8 1101 => D 0100 => 4 1001 => 9 0000 => 0 0000 => 0 0010 => 2 0000 => 0 Answer Q5: As given, i is stored in register s0 and count is stored in register s1. MIPS assembly code with comments jmp loopcond ;Jump to the condition first loopbody addi $s1,5 ;Body of the loop, add immediate value 5 to register DEC $s0 ;Decrement value of s0 by 1 loopcond cmp $s0,0 ;Compare the register value with 0 jg loopbody ;If greater than 0, jump to body

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SOLUTION: Homework

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