A charged cloud system produces an electric field in the air near Earth’s surface. A particle of charge -2.0  10-9 C is acted o

Question

A charged cloud system produces an electric field in the air near Earth&rsquo;s surface. A particle of charge -2.0 r10-9 C is acted on by a downward electrostatic force of 3.0 r10-6 N when placed in this field. (a) What is the magnitude of the electric field? What are the (b) magnitude and (c) direction of the electrostatic force Fel on the proton placed in this field? (d)What is the magnitude of the gravitational force Fg on the proton? (e) What is the ratio Fel /Fg in this case?

brightSpark · Answer

(b) The magnitude of the electrostatic force on a proton is
Fel = eE = (1.60 &times; 10&ndash;19 C) (1.5 &times; 103 N/C) = 2.4 &times; 10&ndash;16N.
(c) A proton is positively charged, so the force is in the same direction as the field, upward.
(d) The magnitude of the gravitational force on the proton is
Fg = mg = (1.67 &times; 10&ndash;27 kg) (9.8 m/s2) = 1.6 &times; 10&ndash;26N.
 
The force is downward.

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A charged cloud system produces an electric field in the air near Earth’s surface. A particle of charge -2.0  10-9 C is acted o

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