Statistics 15

Question

Please write answer beside the question. no explanation needed.

MarkLester · Answer

Step 1
we knows that,margin of error = Z a/2 * (standard error)confidence interval = x ± margin of error----------------------------------------------------------------------------------------
Step 2
from the context of problem we knows that,confidence interval = [ 63.3 , 70.7][ x - margin of error, x + margin of error ] = [ 63.3 , 70.7]=> lower = x - margin of error = 63.3 & and upper = x + margin of error =70.7=> subtract the lower limit from upper limit=> [ upper - lower ] = 70.7 - 63.3=> [ x + margin of error - (x - margin of error) ] = 70.7 - 63.3=> [ x + margin of error - x + margin of error ] = 7.4=> [ 2 margin of error] = 7.4=> margin of error = 3.7

nitesh_rai · Answer

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Statistics 15

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