Trigonometry problems

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SKP.NAMAN · Answer

This is the best solution.

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omsinghpatel · Answer

in first page solution of question no 3 and half part of question no4 and in 2nd page remaining solution of question no4 and question no 5 also.

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satis · Answer

5 arccos [ (y - π )/2] = 5π  arccos [ (y - π )/2] = π  (y - π )/2 = cos π   (y - π )/2  = -1y = π - 24.  arcsin x = arctan 24/7        x = sin ( arctan 24/7 )Let arctan 24/7 = θ   and so  x = sin θ tan θ = 24/7,tan θ =  p/b ,   p = 24n, b = 7n,  h = √  [  p^2 + b^2 ] = √ [  (24n)^2 + (7)^2 ] = 25n Hence,  sin θ = 24/25  or   x = 24/25 = 0.965. Let cos^-1 x = sin^-1 4/5 = θx = cos θ  and  sin θ = 4/5  sin θ = p/h ,  p = 4n, h = 5n.  so b = √[ h^2 - p^2 ] = √[ 5n^2 - 4n^2 ] = 3nx = cos θ  = b/h = 3/5x = 3/5 = 0.6

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Trigonometry problems

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