Qualitative analysis

Question

How do we distinguish sulphate and sulphite ions?

Answer

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Answer

Sulphate ion:Barium chloride test-The addition of a sulfate to a barium chloride solution produces a white precipitate of barium sulfate. This precipitate is very insoluble, not dissolving in any common laboratory reagents.
Magnesium sulfate + Barium Chloride -> Barium sulfate + Magnesium Chloride
MgSO4(aq)+BaCl2(aq)→BaSO4(s)+MgCl2(aq)
Sulphite ion:
Test with Lead acetate Pb(CH3COO)2 :  Take 2ml sodium carbonate extract in a test tube and add lead acetate solution. White precipitate of lead sulphite (PbSO3) is formed.
SO32- + Pb2+ ⟶ PbSO3
Filter the precipitate and add dilute nitric acid HNO3. If precipitate gets dissolved in nitric acid, it confirms sulphite.

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