Answer to Question 1We start by finding the X value of the vertex. X= -b/2a X = -368/(2(-16) = 368/32 = 11.5So after 11.5 seconds, the projectile reaches its maximum height. Answer to Question 2What's the height (y-value) after 11.5 seconds?H = -16t^2+368t H = -16(11.52) + 368(11.5) H = -16(132.25) + 4232 H = -2116 + 4232 H = 2116