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If lines drawn through AB and CD mRSQ = 280o m∠XYZ = 76o mXZ = 140o and mXSZ = 220o and comparing triangles ABP and CDP : DP = AP = 6m and PB=PC = 8m BD = DP + PB = 6m+8m = 14m mRSQR at center = 360 o ∠ROQ = mRSQR – mRSQ = 360 o - 280o = 80o So mXZ at center = 2 x m∠XYZ = 2 x 76o = 152o Hence measure of XYZ at center = 360o - 152o = 208o m∠XYZ =180o - mXZ = 180o - 140o = 40o 7. E be the midpoint of BD BE = ED = 52cm/2 = 26 cm PE = PB + BE = 4 + 26 = 30cm Radius of the circle be = AC = AD = r AE2 = AD2 – ED2 = r2 – 262 AP2 = AE2 – PE2 = r2 – 262 + 302 = r2 + 224 PC2 = AP2 – AC2 = r2 + 224 - r2 = 224 PC = √224 = 14.97

Hi rorojo94... hope to enjoy it. I was a mathematics Olympiad student in my high school. so every math problem that you have, can assign me. I would be happy. I would be online everyday too. every question you had about this answers let me know surely ;)