If a right angle triangle has 10m an Question

Question

If a right angle triangle has 10m and 6m opposite and adjacent sides respectively, then find the hypotenuse of the triangle

satis · Answer

hypotenuse = sqrt [ (base)^2 + (height)^2 ] = sqrt [ 6^2 + 10^2 ] = sqrt [ 36 + 100 ] = sqrt [ 136 ] = 11.66

Garjmi-med · Answer

given: opposite side = 10 m adjacent side = 6 m this is a right-angled triangle. to find the hypotenuse

cc

, use the pythagorean theorem:

c=(opposite)2+(adjacent)2c = \sqrt{( ext{opposite})^2 + ( ext{adjacent})^2}

calculate:

c=102+62=100+36=136c = \sqrt{10^2 + 6^2} = \sqrt{100 + 36} = \sqrt{136}

c≈11.66 mc \approx 11.66 ext{ m}

answer: the hypotenuse is approximately 11.66 meters.

vikyshop2025 · Answer

given a right-angled triangle with: opposite side = 10 m adjacent side = 6 m we need to find the hypotenuse

cc

. use the pythagorean theorem:

\sqrt{( ext{opposite})^2 + ( ext{adjacent})^2}

\sqrt{10^2 + 6^2} = \sqrt{100 + 36} = \sqrt{136}

=100+36 =136

\approx 11.66 ext{ meters}

TheMagicMantleZA · Answer

please see the attached for a step by step solution.

HASSAN_JAMIL123 · Answer

opposite =10 m and adjacent =6 m are the two legs of the right triangle.hypotenuse satisfies pythagoras:
hypotenuse =√(10^2+6^2) ≈  11.66 m