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Phase 1:A bus starts from rest at point A and accelerates at the rate of 0.8 m/s^2 unit it reaches a speed of 12 m/s.</strong></p> <p>v = u + at </p> <p>12 = 0 +(0.8*t)</p> <p>Time taken to accelerate,t= 12/(X.X) = XX seconds <XXXXXX XXXXX="redactor-inline-XXXXXXXXX">[XX = XX XXXXXXX]</strong></p> <p>XXXXXXXX XXXXXXXX while accelerating to 12 m/s, s = ut + (1/2)*a*(t^2)</p> <p>s = (0*t) + 0.X* X.X *(XX*XX) = 90 m</p><p><XX></p><p><XXXXXX XXXXX="XXXXXXXX-XXXXXX-XXXXXXXXX">Phase X:XXXXXX XXXXXXXX XX 12 m/s until XXX breaks are applied; it comes XX XXXX XX point X, 42 m beyond XXX point XXXXX XXX XXXXXX XXXX XXXXXXX</XXXXXX><XX></p><p>XXXXX XXXXXXXX = XXX m</p><p>Initial XXXXXXXX covered while accelerating = 90 m</p><p>Distance XXXXXXX while de-accelerating = 42 m</p><p>Thus, distance covered XX 12 m/s uniform XXXXX =XXX - (90+42) = 300 - XXX = XXX m</p><p>XXXX taken XX XXXXX 168 m,</p><p>t = distance covered / XXXXXXX XXXXX = XXX / XX =14 XXXXXXX <strong XXXXX="redactor-inline-XXXXXXXXX">[t2 = 14 seconds]</XXXXXX></p><p><XXXXXX XXXXX="redactor-inline-converted"><XX></strong></p><p>XXXX XX m/s, it comes to rest (XXXXX speed = X)</p><p>v = u +XX</p><p>X = XX +XX</p><p>XX, at = -12</p><p><br></p><p>Distance XX de-XXXXXXXXXX = 42 m</p><p>Using, s = ut + (1/2)*a*(t^X)</p><p>XX = (12*t)+(X/X)*a*(t^t)</p><p>42 = t *(12 +(X/X)* a* t)</p><p>XXX value XX = -XX</p><p>42 = t * (XX - 6 )</p><p>t = X XXXXXXX <strong class="XXXXXXXX-inline-converted">[XX = 7 seconds]</XXXXXX></p><p><strong>Total time = XX + t2 +XX = 15 + 14 +X = XX XXXXXXX</XXXXXX></p> <p><br></p> <p><br></p>">
