Toggle navigation
Ask Questions
Ask
Answer Questions
Answer
Users
FAQ
Login
Register
Preview 50% of the Answer Below
Due to formatting, images, tables, or paragraphs may be out of place or not shown. Rest assured that they will be included and formatted correctly in your purchased answer.
Details
Question Title:
Need help with question
Go Back to the Question
Answer Preview
Phase 1:A bus starts from rest at point A and accelerates at the rate of 0.8 m/s^2 unit it reaches a speed of 12 m/s.</strong></p> <p>v = u + at </p> <p>12 = 0 +(0.8*t)</p> <p>Time taken to accelerate,t= XX/(0.X) = 15 XXXXXXX <XXXXXX XXXXX="XXXXXXXX-XXXXXX-converted">[XX = 15 XXXXXXX]</strong></p> <p>XXXXXXXX traveled XXXXX XXXXXXXXXXXX to XX m/s, s = ut + (1/X)*a*(t^2)</p> <p>s = (0*t) + X.5* X.8 *(15*15) = 90 m</p><p><XX></p><p><strong class="XXXXXXXX-XXXXXX-XXXXXXXXX">XXXXX 2:Itthen proceeds at XX m/s XXXXX XXX breaks are XXXXXXX; it XXXXX XX rest at point X, 42 m beyond the XXXXX XXXXX the XXXXXX were applied</XXXXXX><XX></p><p>Total XXXXXXXX = 300 m</p><p>XXXXXXX distance covered while accelerating = XX m</p><p>Distance covered while de-XXXXXXXXXXXX = 42 m</p><p>XXXX, distance XXXXXXX at XX m/s uniform XXXXX =300 - (XX+42) = XXX - XXX = XXX m</p><p>XXXX taken XX cover XXX m,</p><p>t = distance covered / uniform speed = XXX / 12 =14 XXXXXXX <XXXXXX class="XXXXXXXX-inline-converted">[t2 = XX seconds]</XXXXXX></p><p><strong class="redactor-XXXXXX-XXXXXXXXX"><br></strong></p><p>XXXX 12 m/s, it comes to rest (final speed = 0)</p><p>v = u +at</p><p>X = XX +XX</p><p>So, at = -12</p><p><XX></p><p>XXXXXXXX XX de-XXXXXXXXXX = 42 m</p><p>XXXXX, s = ut + (1/X)*a*(t^2)</p><p>42 = (12*t)+(X/X)*a*(t^t)</p><p>42 = t *(XX +(1/X)* a* t)</p><p>XXX value XX = -XX</p><p>42 = t * (12 - 6 )</p><p>t = X seconds <XXXXXX class="XXXXXXXX-inline-XXXXXXXXX">[t3 = 7 seconds]</XXXXXX></p><p><strong>Total time = t1 + XX +t3 = 15 + 14 +7 = XX seconds</strong></p> <p><br></p> <p><br></p>">
