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Phase 1:A bus starts from rest at point A and accelerates at the rate of 0.8 m/s^2 unit it reaches a speed of 12 m/s.</strong></p> <p>v = u + at </p> <p>12 = 0 +(0.8*t)</p> <p>Time taken to accelerate,t= 12/(X.8) = 15 XXXXXXX <strong class="XXXXXXXX-XXXXXX-XXXXXXXXX">[XX = 15 seconds]</strong></p> <p>XXXXXXXX traveled while accelerating XX XX m/s, s = ut + (X/X)*a*(t^2)</p> <p>s = (0*t) + 0.X* 0.X *(XX*15) = 90 m</p><p><XX></p><p><strong class="XXXXXXXX-inline-XXXXXXXXX">Phase X:XXXXXX proceeds XX 12 m/s XXXXX XXX breaks are applied; it XXXXX to XXXX at XXXXX X, XX m XXXXXX the point where the breaks were applied</strong><br></p><p>XXXXX Distance = XXX m</p><p>XXXXXXX distance covered XXXXX XXXXXXXXXXXX = XX m</p><p>XXXXXXXX XXXXXXX while de-accelerating = 42 m</p><p>XXXX, XXXXXXXX XXXXXXX at XX m/s uniform XXXXX =XXX - (XX+XX) = XXX - XXX = 168 m</p><p>XXXX XXXXX to cover 168 m,</p><p>t = distance XXXXXXX / XXXXXXX XXXXX = XXX / XX =14 seconds <XXXXXX XXXXX="redactor-inline-converted">[XX = 14 seconds]</XXXXXX></p><p><strong XXXXX="redactor-inline-converted"><XX></XXXXXX></p><p>XXXX XX m/s, it comes to rest (XXXXX XXXXX = X)</p><p>v = u +at</p><p>X = 12 +at</p><p>So, XX = -12</p><p><XX></p><p>Distance to de-XXXXXXXXXX = 42 m</p><p>XXXXX, s = ut + (1/2)*a*(t^2)</p><p>42 = (XX*t)+(1/2)*a*(t^t)</p><p>XX = t *(12 +(1/2)* a* t)</p><p>Use XXXXX at = -XX</p><p>XX = t * (XX - X )</p><p>t = 7 seconds <XXXXXX class="redactor-XXXXXX-XXXXXXXXX">[t3 = 7 XXXXXXX]</XXXXXX></p><p><strong>XXXXX time = XX + XX +XX = 15 + 14 +X = 36 XXXXXXX</XXXXXX></p> <p><br></p> <p><br></p>">
