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Phase 1:A bus starts from rest at point A and accelerates at the rate of 0.8 m/s^2 unit it reaches a speed of 12 m/s.</strong></p> <p>v = u + at </p> <p>12 = 0 +(0.8*t)</p> <p>Time taken to accelerate,t= XX/(0.X) = 15 seconds <strong XXXXX="XXXXXXXX-XXXXXX-converted">[XX = 15 XXXXXXX]</XXXXXX></p> <p>XXXXXXXX traveled while XXXXXXXXXXXX XX XX m/s, s = ut + (X/X)*a*(t^X)</p> <p>s = (X*t) + X.X* 0.8 *(XX*15) = 90 m</p><p><br></p><p><XXXXXX XXXXX="redactor-inline-XXXXXXXXX">XXXXX X:Itthen proceeds XX 12 m/s until XXX XXXXXX XXX applied; it XXXXX to rest at point B, XX m XXXXXX the XXXXX XXXXX XXX breaks were XXXXXXX</XXXXXX><XX></p><p>Total XXXXXXXX = 300 m</p><p>XXXXXXX distance XXXXXXX while XXXXXXXXXXXX = 90 m</p><p>XXXXXXXX XXXXXXX XXXXX de-accelerating = 42 m</p><p>Thus, XXXXXXXX covered XX XX m/s uniform XXXXX =300 - (XX+42) = 300 - 132 = XXX m</p><p>XXXX XXXXX to XXXXX 168 m,</p><p>t = distance XXXXXXX / XXXXXXX XXXXX = 168 / 12 =14 XXXXXXX <strong class="XXXXXXXX-XXXXXX-XXXXXXXXX">[t2 = 14 seconds]</XXXXXX></p><p><XXXXXX class="XXXXXXXX-inline-converted"><XX></XXXXXX></p><p>XXXX 12 m/s, it comes XX rest (final speed = X)</p><p>v = u +at</p><p>0 = XX +XX</p><p>XX, XX = -12</p><p><XX></p><p>XXXXXXXX to de-XXXXXXXXXX = 42 m</p><p>Using, s = ut + (1/2)*a*(t^2)</p><p>XX = (XX*t)+(X/2)*a*(t^t)</p><p>XX = t *(12 +(X/2)* a* t)</p><p>XXX value at = -12</p><p>XX = t * (XX - 6 )</p><p>t = 7 XXXXXXX <strong XXXXX="XXXXXXXX-XXXXXX-XXXXXXXXX">[XX = X seconds]</XXXXXX></p><p><XXXXXX>XXXXX XXXX = XX + t2 +XX = XX + 14 +7 = 36 XXXXXXX</strong></p> <p><br></p> <p><XX></p>">
