DE is a chord because D and E points are from the circle with EB as diameter.A is a point of tangency because it is the only point where AH “touches” the circle mentioned beforeC is the ceXXXX XX the XXXXXXX mentioned at XXX XX a XXXXXXX XX both XXX XXXXXXX in X, XXXXXXXXXXXX in H.XX XX a radius, XXXXXXX A XX XXXX XXX circle and C is centerXX XX a XXXXXX.XX XX a diameterMN XXXXXXXX so: XX+XX+XX=180 MA=55, CN=XX so XX is 60 in order XX XXXXXXX XXX value of the XXX.XX XX opposite to MA, so XX=55XXX angle subextendes NB arc, so BEN measures 55 degreesACN XXX is XX+CN=XX+65=125MAC=MA+XX=55+60=XXX13.XXX=XX+AC+XX+XX=55+XX+XX+XX=235
XX. x=17/8=X.125, XXXXXXXXXXX in the XXX named XX
XX. x=5, explanation in the jpg’s named XX – X XXX XX - X
XX. AC is XXX XXXXXXX XXXXXXX it is the XXXXXX XX the opposite XXXXX, and that XXXXX XXXXXX XXXX a XXXXXX XXXXX and it XXXXXXXX XX XXXXXXX.
XX. XXX same idea XXX XXX angle XX unknown, so XX the XXX XXXXXXXX XX XXXXXXX, XXXX angle ABC measures XX degrees.
18. AC measures 130 degrees
XX.XXXXX ABC XXXXXXXX XXX XXXXXXX
20. XXXXX 1 measures 130 degrees
XX. MLK XXXXXXXX XX XXXXXXX because the XXXXXX arc MK measures 270 (XXXXX) so the XXXXXXX one measures XX (XXX sum must be XXX) so XXXX XX XX is 45 according XX the theorem XX angles touching the XXXXXX.
XX. XX we consider XXX radiuses and form a triangle XXX, with X XX center XX XXX XXXXXX XX will obtain XXX and XXX XXXXXX measuring XX XXXXXXX (XXX XX XXX radiuses XXXXX a XX XXXXXXX XXXXX XXXX the XXXXXXXXXX XXXXXXX of XXX circle) so ACB angle XX 160 (the XXX XX angles in a XXXXXXXX is 180) C XX the XXXXXX, so XXX arc XXXXXXXX XXX degrees.
XX.X measures XX XXXXXXX 105+2x1+125 XXXX be 360 so XXX=360-XXX XXXXXXXXX XXX=XXX so 1=XX
XX.X XXXXXXXX 29 degrees
25.X XXXXXXXX 27, X XXXXXXX
XX. center XXXXXXXXXXX (-X, X)
27. radius=6 because XXXXXX XX square is 36
XX. (-1,X)
XX. radius=X.X because radius XX XXXXXX is X.25
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