XX you XXX, XX get XX^-X XXX XXX XX X+.
Since glycine XXXX XXXXXX XXX equilibrium because of XXX new X+ (common ion effect), XX XXXX XX XXX the XXXXXXXXX XXXXXXXXXX XXXXXXXX:
This XX the form you XXXX, but XX're going XX use the XXXX XXXXX XXXX XXXXX we don't know how XXXX X+ we XXXX in the first XXXXX (XXXX how XXXX we are adding). XXX XXX't we know? XXXXXXX, just XXXX with any XXXXXXXXXXX XXXXXXXX, if you add a XXXXXXX, the reaction XXXX lean XXXXXXX the reactants. The addition XX H+ means XXXXXXX XXXX XXXX XXXX some of XXX H+ it XXX (XXXXX on XXX XX values). Here's XXX "pure"/original from XX XXX equation XXXXX:
Let's use x in places XXXXX we see XXX disassociation of XXXXXXX. Thankfully, at XXXX pH, glycine disassociates in a XXXXX 1:1 XXXXX (we XXX converting XXX to XX):
XXXXXXX XXX x, XX get X.02503 (N.B.: you'll XXX two values, but you can't have XXXXXXXX XXXXX). XX're XXX done. XXXX is how many X+ is given by glycine. As you XXX XXX XXXX XXX equation above, total H+ XX x + XX^-2
XX now, XXXXX XXXX, XX solve for XXX XXXXXX XX H+:
But XXX't XXXXXX! XXXXX's a XXX XXXXXX! It XXXXX't XXXXXX XXX XXXX, but XXXXXX safe XXXX sorry:
XXX XXXXXX XXX X.XX XX XXXX XXX XX.