XX + 4y120
xX
x,y0
Here XXX Z = X(x + 3y) XXXXX parallel to XXXXXXXXXX x + XXXX
then XXXX L.P.P has more XXXX XXX solution.
JUSTIFICATION
x + 3y = XX
3x + XX120
Corner point
A = (5, 0)z = 10
B = (X, 18.XX) X = 120 XXX
X = (24, XX)X = XXX XXX
X = (40, 0)z = XX
X = 120 XX XXXXXXX XXXXXXXX XX (5, 18.XX) & (XX, XX)
The XXXXXXX is XXXXXXXXX in saying that XXX LP XXXXX requires XXXXXXXXX XXX XXXXXX XXXXXXXXXXX. XXX only assurance XXXX an XX model is the definitive relationship XXXXXXX XXXXXXX variables XXX XXX target XX be XXXXXXXXX.
In XXXXXXXX, the base XXXX XXXXXXXX or the XXXXXX XXXXXXXXXX XX the base XXXX may be used XX XXXXXXXXX a XXXX defined LP XXXXX. XXX results of XXXX baseline case model provide a XXXX XXXXXXXXXX XXXXXXXXX for operations XXXXXXXXXXXX.
In order XX take care XX the XXXXXXXXXXX XXX XXXXXXXXXXX, it XX XXXXXXXX XX run a number XX XXXXXXXXX XX varying XXX values XX the variables which would create XXXXXXXXX XXXXXXXXX XXXXXX XXX different XXXXXXXXX function XXXXXX. XXXXXXXXX, a XXXXXXXXXXX XX XXXXXXXX planning and LP analysis XXX XX used XX XXXXXX out a XXX of feasible values that XXX suitable XX XXXXXXX levels.
XX addition, a solved LP model's XXXXXXXXXXX performance in MS Excel provides XXX XXXXXXXXXXX XXXX XXXXX itself XX XXXX an XXXXXXXX. XXX XXXXXXX XXXX and XXX binding or non-binding XXXXXXXXXXX XXXXXXXX in the sensitivity analysis XXXXXXXXXXX XXX degree XX which those XXXXXXXXXX XXX be varied, XXXXXXX affecting the solution's XXXXXXXXXX.
XXXX LP modeling can XX used XXXX well in XXXXXXXXXX where XXXXX is XXXXXXXXX XX construct a XXXX variety of XXXXXXX solutions, depending on XXX XXXXXXXXXX situations.