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Explain CMRR IN AN OP-AMP
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</figure><p>XXX XX the XXXXXXX XX XX achieve XXX XXX of XX,v2,XX in amplified form at XXXXXX terminal.</p><p>XXX as XXX XX-XXX XXX a very XXXXX input XXXXXXXXX, XXXXX will XX current going into XXX Op-XXX.</p><p>Therefore, i = XX+XX+i3 is what flowing XX XXX output side. Also XXXXX XX a virtual short between XXX XXXXXX A and X, there for voltage XX XXXXX two XXXXX will XX equal. X point is at XXXXXX there the point X XXXX also be XX 0 XXXXX. XXXXXXXXXXX these lets XXXX XXXX XXXXXXXX.<br></p><figure><XXX src="https://XXXXXXXXXXXX.XX.XXXXXXXXX.XXX/media/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.52.XXXX.XXXX" data-s3="XXXXX://schoolsolver.s3.XXXXXXXXX.com/XXXXX/attachments/370WhatsAppImage20200630at9.52.35AM.jpeg"></XXXXXX><p>Equating the currents XX input XXX XXXXXX side,</p><figure><XXX src="XXXXX://XXXXXXXXXXXX.s3.amazonaws.XXX/XXXXX/attachments/476WhatsAppImage20200630at9.52.55AM.XXXX" XXXX-s3="XXXXX://XXXXXXXXXXXX.XX.XXXXXXXXX.XXX/XXXXX/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.52.55AM.jpeg"></XXXXXX><p>To achieve XXXXXXX we will XX XXXXXXX,</p><figure><img XXX="https://XXXXXXXXXXXX.XX.XXXXXXXXX.com/XXXXX/XXXXXXXXXXX/659WhatsAppImage20200630at10.XX.XXXX.XXXX" data-s3="https://schoolsolver.XX.XXXXXXXXX.XXX/media/attachments/659WhatsAppImage20200630at10.07.XXXX.jpeg"></XXXXXX><p>XXXX XXX XXXXXX will be,</p><XXXXXX><XXX src="https://schoolsolver.XX.XXXXXXXXX.com/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.XXXX.XXXX" XXXX-s3="XXXXX://schoolsolver.s3.amazonaws.com/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.XXXX.jpeg"></XXXXXX><p><XX></p><p><XX></p><p>XXX let's XXXX onto the differential amplifier XXXXXXX.</p><p>XXX circuit looks XXXX,</p><figure><img src="XXXXX://schoolsolver.XX.XXXXXXXXX.XXX/media/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.53.XXXX.jpeg" data-XX="XXXXX://XXXXXXXXXXXX.s3.amazonaws.XXX/media/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.47AM.jpeg"></XXXXXX><p>XXXX XXXXXXX XXXX applies and the XXXXXXX short makes XXXXXXX XX point A (VA) XXXX be XXXXX to XXXXXXX at point X(VB).</p><p>Now hold XX! XXXX's XX should XX?</p><p>VB XX w the voltage drop XXXXXX R3 resistor, XXXXX XX,</p><XXXXXX><img src="XXXXX://XXXXXXXXXXXX.XX.XXXXXXXXX.XXX/XXXXX/attachments/164WhatsAppImage20200630at9.XX.XXXX.jpeg" XXXX-XX="XXXXX://schoolsolver.XX.XXXXXXXXX.XXX/media/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.00AM.XXXX"></XXXXXX><p>Let's get into current analysis,</p><p>The XXXXXXX i1 is what XX XXXX XXXXXXX at XXX output XXXX because XX XXXX input XXXXXXXXX of XXX XX-XXX, <br></p><p>equating XXX current of XXXXX XXX XXXXXX XXXX,<XX></p><XXXXXX><img src="https://schoolsolver.s3.XXXXXXXXX.com/media/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.18AM.XXXX" XXXX-XX="XXXXX://XXXXXXXXXXXX.s3.XXXXXXXXX.XXX/XXXXX/XXXXXXXXXXX/851WhatsAppImage20200630at9.54.18AM.XXXX"></figure><p>XXXXXXX XXXXXXXXXXXXX,</p><figure><XXX XXX="XXXXX://schoolsolver.XX.amazonaws.XXX/media/XXXXXXXXXXX/463WhatsAppImage20200630at9.XX.XXXX.jpeg" XXXX-XX="https://XXXXXXXXXXXX.XX.amazonaws.XXX/media/XXXXXXXXXXX/463WhatsAppImage20200630at9.54.XXXX.XXXX"></figure><p>So, output XXXXXXX becomes,</p><XXXXXX><XXX XXX="XXXXX://schoolsolver.s3.amazonaws.XXX/media/XXXXXXXXXXX/973WhatsAppImage20200630at9.XX.XXXX.jpeg" XXXX-XX="XXXXX://XXXXXXXXXXXX.s3.XXXXXXXXX.com/media/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.54.XXXX.XXXX"></XXXXXX><p>XXX XX achieve XXX differential XXXXXXXXX XX should do XXX XXXXXXXXX,</p><XXXXXX><img src="XXXXX://schoolsolver.s3.XXXXXXXXX.com/media/attachments/568WhatsAppImage20200630at9.54.XXXX.XXXX" data-XX="XXXXX://schoolsolver.XX.XXXXXXXXX.XXX/media/XXXXXXXXXXX/568WhatsAppImage20200630at9.54.XXXX.XXXX"></XXXXXX><p>Now XXX output becomes,</p><figure><XXX src="https://schoolsolver.XX.XXXXXXXXX.com/media/attachments/026WhatsAppImage20200630at9.55.XXXX.XXXX" data-s3="https://XXXXXXXXXXXX.XX.XXXXXXXXX.com/XXXXX/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.XXXX.jpeg"></figure><p>Differential operation XXXXXXXX!!</p><p><br></p><p><br></p><p>XXX's XXXX onto the problem,</p><p>XXXXXXX the XXXXXXX, it's just a summing XXXXXXXXX and we XXXX put the XXXXXXXX value given in XXX problem XXXX XXX equation XX XXX,</p><figure><XXX src="XXXXX://XXXXXXXXXXXX.XX.XXXXXXXXX.com/media/attachments/798WhatsAppImage20200630at10.17.XXXX.XXXX" XXXX-s3="XXXXX://schoolsolver.s3.amazonaws.XXX/media/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.17.16AM.XXXX"></XXXXXX><p>where,</p><figure><XXX src="https://XXXXXXXXXXXX.XX.XXXXXXXXX.XXX/media/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.38AM.XXXX" XXXX-XX="https://XXXXXXXXXXXX.s3.XXXXXXXXX.XXX/media/XXXXXXXXXXX/807WhatsAppImage20200630at10.XX.XXXX.jpeg"></figure><p>XXXXXXX XXXXX XXXXXX,</p><figure><img src="XXXXX://schoolsolver.XX.XXXXXXXXX.XXX/media/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.XXXX.XXXX" XXXX-XX="XXXXX://XXXXXXXXXXXX.s3.amazonaws.XXX/media/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.XXXX.jpeg"></XXXXXX><p>XXXXXX will XX -XXX.<XX></p><p><br></p><p><XX></p>">
