P=9d+320
797.00=9d+320
XXX.00-XXX=9d
XXX=9d
477/X=d
53=d
The of articles is 53
2. X XX partly XXXXXXXX and partly varies with V. When X 40, D = XXX XXX when X = XX, D = XXX. i) Find the XXXXXXX XXXXXXXXXX D XXX V.
D = mV + C , ( XXXXXX XXXXXXXX y = XX + b) (XX) Find D when V= 73.
XXXX V=40, X=150 XXX = 40m + C ** XXXX V=54, X=XXX 192 = 54m + C *** XXXXXXXX ** from *** XX = 14m m = X sub XXXX ** , XXX = 120 + X C = XX D = 3V + XX X=3*XX+XX=XXX
X.(a) X XXXXXXXXXXX XXXX for XXXXXXX oil XXX a XXXXXXXX of 1078 cm³. XX XXX height XXX XXXXXX are XXXXX, XXXXXXXXX the depth XX XXX in the tank when full (XXXX π= XX/X)
Volume of XXXXXXXX=
XXXX r XXX h XXX equal
So, XX2×r=1078
XXX=XXXX
rX=XXXX/X
rX=1078/(XX/X)
rX=(XXXX/22)*7
r3=XX*7
rX=X*X*7
rX=XX
r=7
r=7 XXX h=7
Therefore, XXX XXXXX of XXX XXXX when full XX XX.
(b) Find the XXXXXXXXX XX a rectangular XXXXX which is 10m by XX.
Length (l) = XXXX XXXXX (w) = XXX Perimeter XX the XXXXXXXXX = X(l + w) units X = 2(10 + X) X = X (15) X = 30 Thus, XXX perimeter of the rectangle XX 30 m.
4.Solve the equation: X-4-2/X=-X/X