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sir what does this mean
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<p>We also use the order of operations BODMAS which is used to solve math problems.</p> <p>Where B stands for Brankets, O - Order/Indices/Powers, D - Divide, M - Multiply, A - Addition and S- Subtraction.</p><p>This means we solve brackets eg "(), [], {}" first, then we solve the powers/indices eg square root or squared, then divide, XXXX XXXXXXXX and XXXXXX solve using addition XXX subtraction XXXX left XX right.</p><p><XX></p> <p>X + [12 - {8 + X - (9 of X + 1- 13 x 4)}]</p> <p><XX></p> <p>XXXX 1:</p> <p>XX XXXXX the numbers or terms in XXX brackets first. XXXXX XXXXX are 3 sets XX XXXXXXXX. XX XX XX the XXXXXXX XXXX in XXX two XXXXXXXX. XX XX solve(X XX 6 + X- 13 x 4) first. XXXXXXXX, the word "of"means to multiply so change XXX word XX the XXXXXXXXXXXXXX XXXX "x".</p> <p>(9 XX 6 + X- 13 x 4)<br></p> <p>(X x 6 + 1- XX x X)<br></p> <p>Since we XXXX XXX XXXXXXXX, "X", XX XXXX XX order, "X". XXXXX XXX XX XXXXXX in XXX problem so we XXXX XX XXXXXXXX, "X". There XXX no division XXXXX so XX XXXX XX XXXXXXXXXXXXXX, "X". XXXXX you XXX XXX "x" XXXX, XXXXXXXX XXX two XXXXXXX that the "x" XX XXXXXXX.</p> <p>(X x X + X- 13 x 4)}]<XX></p> <p>=(54 + 1 - 52)</p> <p><XX></p> <p>XX did the XXXXXXXXXXXXXX, "M" so XX move to addition, "X" XXX subtraction, "S".</p> <p>XXXX: XXXX XXXXX is addition and XXXXXXXXXXX only in the brackets or XXXX XXX, XX solve XXXX left XX right.</p> <p>So,(54 + 1 - 52)</p> <p>= (XX-XX)</p> <p>= (3)</p> <p>=3</p> <p>XXXXX we are left with XXX XXXXXX, we drop XXX brackets.</p> <p><br></p> <p>STEP X:</p> <p>XX XXXXXX XXX first XXX XX brackets, we XXX put that value into the second set XX XXXXXXXX.</p> <p>XX, {8 + X - (9 XX 6 + 1- XX x 4)}</p> <p>= {X + 3 - (3)}</p> <p>={ X + 3 - 3} *Remember to drop XXX bracket.</p> <p>= { XX - 3}</p> <p>= { 8} *XXXXX we are XXXX with XXX XXXXXX, XX drop the XXXXXXXX.</p> <p>= X</p> <p><br></p> <p>We have XXXXXX two XXXX of XXXXXXXX. XXX, we solve XXX XXXX XXX of XXXXXXX,</p> <p>[XX - {8 + X - (9 XX 6 + X- 13 x 4)}]<br></p> <p>= [XX - {8} }</p> <p>= [4]</p> <p>= 4</p> <p><XX></p> <p>So if you XXX XXX XXXXXX in the sum as a XXXXX,</p> <p>X + [XX - {8 + X - (9 XX 6 + X- 13 x X)}]</p> <p>= 7 + [12 - {8 + 3 - (9 x X + X- XX x 4)}]<XX></p> <p>= X + [12 - {8 + X - (54 + 1- XX)}]<XX></p> <p>= X + [12 - {X + 3 - (3)}]<br></p> <p>=X + [XX - {8 + X - X}]<br></p> <p>= X + [12 - {8}]</p> <p>= X + [XX - X]<br></p> <p>= 7 + [ 4 ]</p> <p>= 7 + 4</p> <p>= XX</p> <p></p> <p><XX></p> <p><br></p>">
