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sir what does this mean
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<p>which XX X*X= 54, 13*4= XX in the below step</p> <p>7+[12-{8+X-(XX+X-52)}]</p> <p>in the next XXXX XX look XXX "X" in XXXXXX which is divison XXXXXXX XXXXXX brackets, since there XXX no XXXXXXXX, continue with next which XX "X" XXXXX XX solved XXX XXX XXXXXXXXXXXXX brackets, so XXXX is "X" which is XXXXXXXXX is XXXXX itpresent XXXXXX XXXXXXXX, which is XX+X= 55 , in XXX below step<br><XX></p> <p>X+[12-{X+X-(XX-XX)}]</p> <p>in the XXXX order we XXXXXX XXXX for "S" in XXXXXX XXXXX is subtractionpresent inside XXXXXXXX, which XX 55-XX, solve as in next XXXX</p> <p><br>7+[XX-{X+X-(X)}]</p> <p>now eliminating XXX brackets again , XXX XXXX XXXX<XX>7+[XX-{8+3-3}]</p> <p>so XXXXX XXXX for XXXXXX, XXXXX there XX no divison XXX XXXXXXXXXXXXXX ,next XX "A" XXXXX is additions is XXXXX itpresent XXXXXX brackets, XXXXX XX X+3=11<br></p> <p>7+[XX-{11-X}]<br></p> <p>so again XXXX XXX BODMAS, since there XX no XXXXXXX XXXXXXXXXXXXXXXXX and addition in the brackets, so solve XXX "S" subtraction, which is 11-3=8, as show XXXXX</p> <p>7+[12-8]</p> <p>now XXXXX solve,look XXX BODMAS, since XXXXX is no XXXXXXX andmultiplication XXX XXXXXXXX in XXX brackets, so solve XXX "S" XXXXXXXXXXX, XXXXX XX XX-8=4, as XXXXX below</p> <p><br>X+4</p> <p>now add<br>XX</p> <p>so the answer XX XX</p>">
