C = n/X = (1.XXXXX mmol)/(XX.XX XX) = 0.XXXX mol/L
XXX molarity XX XXX HCl solution is 0.077 X.
4. The addition of XXX XXXXX XXXX XXX interfere since the amount of XXXXX XXXX was XXXXX XX XXXXX. The XXXXXXXXXXXXX XX the XXXXXXXX XXXXXX "XX" XXX be calculated XX usual, XXX XXXX the XXXXXXXX equation XXX XX applied to find XXX XXXXXXXX molarity "XX" XX the XXX XXXXXX:
C1 = XXXX/V1 = XX(XX.XXXX/15.XX mL)