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Euler circuit
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</XXXXXX><p>XX, to XXXXXXXXX XXX type of the XXXXX XXXXX i.e. XXXXXXX it's an XXXXX path or XXXXX circuit, we'll start XXXX path formation XXXXXX over the edges only once XXX XXXXXXXXXXX XXXXXXX XXX XXXXXXXX XXX ending XXXX XX XXXX or XXX.</p><p>We'll XXXX XXX path in order XX follows:</p><p>1(XXXXX) - 2 - 6- X - X - X - XX - 10 - 9 - 18 - 12 - X - 15 - 14 - 13 - 19 - 21 - 22 - XX - 23 - 25 - 24 - XX - XX - X - X (end)</p><XXXXXX><XXX XXX="https://schoolsolver.s3.XXXXXXXXX.XXX/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXX.png" XXXX-s3="XXXXX://schoolsolver.s3.amazonaws.com/XXXXX/attachments/XXXXXXXXXXXXXXX.png"></figure><p>Since, XXX XXXXXXXX and finishing XXXXXX are XXXX, the XXXXX is an <XXXXXX>Euler XXXXXXX.</XXXXXX></p><p>A video has been attached XX give XXXXXXXXXXXX XXXXXXXXXXX XX XXX XXXX formation of XXX XXXXXXXX.</p><p><XX></p><h4>Brute XXXXX Algorithm for finding Hamilton XXXXXXXX</h4> <ol><li>XXXX of all possible XXXXXXXX XXXXXXXX, </li><li>Calculate the weight XX XXXX circuit XXXXX in Step 1 </li><li>XXXX the circuit that has the<b>XXXXXXXX</b>XXXXXX.</li></ol><XX>XX, XXX it is used rarely?</XX><p>This method is<b>inefficient</b>, i.e., takes a lot of XXXX. XXX XXXXXX XX XXXX if XX XXXX a complete XXXXX, with N XXXXXXXX then XXXXX are (N-X)! XXXXXXXX to list, calculate XXX weight, XXX then XXXXXX the XXXXXXXX from. XXXX XX we XXX XXXX huge number XX (N-X)! by half, still for N XX XXXXX as 28, the XXXX it takes XXXX XXX XXXXXXX computers of XXX day by<b>XXXXX-XXXXX</b>is longer XXXX XXX age XX XXX universe.XXXX, we normally avoid XXXXX force XXXXXX XXX XXXXXX XXXXXX vertices XXXXXXX then 5.</p>">
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