each other.
So AE = CE
x^2 - 8 = 2x
x^2 - 2x - 8 = 0
(x-4)(x+2)=0
x = 4 or x=-2( invalid due to -ve sign)
AE = 2CE = 2*2x = 2*2*4 = 16
2. XXX XXXXXXXX XX the XXXXXXXXXXXXX XXXXXX XX a parallelogram XX 180°.
XX ∠BCD + ∠XXX = XXX°
∠XXX =180°-∠ABC = 180° - 103° = XX°
X. According to XXX law of parallelogram, opposite XXXXX are XXXXX,opposite XXXXXX XXX XXXXX XXXXXX diagonals XXXXXXeach XXXXX; XXX there are X setssupplementary angles.
So the 1st XXXXXX is XXXXX and XXXX all XXXXX options are Correct XXXXXX.
X.
Statement - Reason
XXXXXXXXXXXXX - XXXXX
KL XX XX XXX XX II XX - XXXXXXXXXX XX parallelogram
m∠X + m∠N =XXX° - XXXX-Side XXXXXXXX XXXXXX XXXXXXX
m∠L + m∠X = XXX° - Same-Side Interior XXXXXX XXXXXXX
m∠X + m∠X=XXX° - Same-XXXX Interior angles Theorem
m∠X+ m∠N =m∠X + m∠X - XXXXXXXXXX Property XX Congruence
m∠L+ m∠X =m∠X + m∠L - XXXXXXXXXX XXXXXXXX of Congruence
m∠N =m∠L - XXXXXXXXXXX Property XX Equality
m∠M =m∠K - XXXXXXXXXXX XXXXXXXX XX Equality
∠N ≅∠L and ∠M ≅∠X - XXXXX Congruence XXXXXXXXX
X.
XXX XXXXXXXXXXX of point C XXX ( a+b,c) .......................................... XX X( a+b, o+c)
XXX XXXXXXXXXXX of the midpoint XX XXXXXXXX XX XXX (a+b/X, c/2) ,,,,,,,,,,, as ( 0+a+b/X, X+c/X)
XXX XXXXXXXXXXX of XXX midpoint of diagonal BD are ( a+b/X, c/2) .............XX ( a+b/X, 0+c/2)
AC and BD XXXXXXXXX at XXXXX X XXXX XXXXXXXXXXX( a+b/2,c/2) ..................midpoint of both XX XXXXX at E
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