QLT1 Task 2
QLT1 Task 4 Revision
RunningHead:Numeracy,Algebra,&Geometry
Numeracy,Algebra,&Geometry RobertGFoster
WesternGovernorsUniversity
Numeracy,Algebra,&Geometry 2
angle BAC=angleDEC=90given
Angle BCA= angleDCE=verticallyopposite angles ACcongruentCE (given)
( BD bisectsAC) AAS Test
Statements | Reasons | Step1 | ?QSU isisosceleswith base ?? | Step1 | It is already given thatRQ=UT | Step2 | ????? | Step2 | SinceQSU isa IsoscelesTriangle | Step3 | ?RQS? ?TUS | Step3 | Included angle RQU= TUS | Step4 | ????? | Step4 | Included angle RQU= TUS | Step5 | ?RQS ??TUS | Step5 | SAS (2,3,4) | Step6 | ????? | Step6 | CPCTC | Step7 | S isthemidpointof?? | Step7 | SAS or Side-angle-sidetheoremstatesthat if2 sidesandtheincluded angle of2triangles are equal, thetriangles are congruent. BySAS theorem,thetriangles RQSandTUSare congruent. So, RS= ST(correspondingsides ofcongruent triangles areequal) Therefore, Sis themidpoint ofRT. |
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So C istheMidpointofDB