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Question Title:
geometry
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Answer to CIRCLE PROBLEMS
DE
A, B, G, H
C, F
XX, XX
XX, CE, CB, FG, FH
XX
BCE
180-(XX+65) = XX
X
Angle of XXX NB = XXX – ( XX+XX) = 55
0
m
&XX;BEN
= m
&XX;XXX =55
0
Angle of arc ACN = XX+65 =XXX
0
Angle of XXX MAC = 180 - 65 = 115
0
Angle XX XXX XXX = 180 + 55 = 235
X
X
2
= 8
2
+ XX or x= (81-XX)/8 = X.125
X
x = (XX
X
-X
X
) / X*X = X
X
XX XXXXX XXX= XX
X
, AC XX diameter. So measure XX arc AC = XXX
0
XXXXX XXX = arc AC /2 = XX
0
/2 = XX
X
Arc AC = X*XXXXX XXX = 2*XX=XXX
0
Angle XXX = XXX AC /2 = 200
0
/X = XXX
X
m<
1 = XXX/X = XXX
0
arc MLK = 135*2 = XXX
X
arc XX = XX*X = XXX
0
<1 = [ XXX –(125+105)]/2 = 65
0
&XX;X = (122-XX)/X = 29
0
<1 = (135-XX)/X = 40
X
(x,y) = ( -X, 4)
r = √XX = X
(x,y) = ( -X, 6)
r = √X.25 = X.X
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