The df(XXXXXXX) = 2 The XX(Within) = XX XXX XXbetween= XXXX.X
MSbetween = XXXX.2 SSXXXXXX= XXXX
MSXXXXXX= XXX.5 XXX X XXXXXXXXX = 3.6101
Claim:The scores XXXXX XXX different groups XXXXXXXXX.
The null and alternative XXXXXXXXXX is:
H1: XX XXXXX XXX XX the mean is not XXXXX.
Level XX significance = 0.05
XXXX XXXXXXXXX F = 3.6101
Critical XXXXX = X.XXXX
XXXX XXXXXXXXX X < XXXXXXXX XXXXX we fail XX XXXXXX null XXXXXXXXXX.
XXXXXXXXXX: The scores among the XXXXXXXXX XXXXXX XXX XXX same.
By using excel we can solve this question easily.
First, XXXXX all XXXX XXXX XXXXX.
XXXXX XX XXXX -------&XX; Data Analysis--------> Anova: XXXXXX-Factor-----> XXXXX Data -------&XX; Select XXX XXXX -------&XX; Output XXXXX : XXXXXX XXX empty cell --------> ok
XX get
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The SSbetween = 5700.X
XXbetween = 2850.2SSwithin = 9474
XXwithinThe X XXXXXXXXX = X.XXXX
XXXXX: The XXXXXX among XXX XXXXXXXXX groups different.
The XXXX XXX XXXXXXXXXXX XXXXXXXXXX XX:
XX: XX XXXXX XXX of the XXXX is XXX equal.
Level of XXXXXXXXXXXX = X.XX
Test XXXXXXXXX F = X.XXXX
Test XXXXXXXXX F &XX; XXXXXXXX XXXXX XX XXXX XX XXXXXX null hypothesis.
XXXXXXXXXX: XXX scores among the XXXXXXXXX XXXXXX XXX XXX same.