each other.
So AE = CE
x^2 - 8 = 2x
x^2 - 2x - 8 = 0
(x-4)(x+2)=0
x = 4 or x=-2( invalid due to -ve sign)
AE = 2CE = 2*2x = 2*2*4 = 16
X. The XXXXXXXX XX the supplementary angles XX a XXXXXXXXXXXXX XX 180°.
XX ∠XXX + ∠XXX = 180°
∠XXX =XXX°-∠XXX = 180° - 103° = XX°
X. XXXXXXXXX XX the law of XXXXXXXXXXXXX, opposite XXXXX XXX XXXXX,XXXXXXXX angles are equal andThe diagonals XXXXXXXXXX XXXXX; but there XXX 4 setssupplementary XXXXXX.
So XXX 1st option XX wrong and XXXX all XXXXX XXXXXXX are Correct XXXXXX.
4.
Statement - Reason
XXXXXXXXXXXXX - XXXXX
KL II XX XXX KN XX XX - XXXXXXXXXX of parallelogram
m∠X + m∠N =180° - XXXX-XXXX XXXXXXXX angles Theorem
m∠X + m∠X = 180° - Same-XXXX XXXXXXXX angles XXXXXXX
m∠X + m∠X=180° - XXXX-Side XXXXXXXX XXXXXX XXXXXXX
m∠X+ m∠N =m∠X + m∠L - Transitive XXXXXXXX of XXXXXXXXXX
m∠L+ m∠M =m∠K + m∠X - XXXXXXXXXX Property of Congruence
m∠N =m∠L - Subtraction XXXXXXXX XX XXXXXXXX
m∠X =m∠K - XXXXXXXXXXX Property of Equality
∠N ≅∠L XXX ∠M ≅∠X - Angle XXXXXXXXXX Postulate
5.
XXX XXXXXXXXXXX XX point C XXX ( a+b,c) .......................................... as X( a+b, o+c)
XXX coordinates XX XXX midpoint XX XXXXXXXX AC are (a+b/2, c/X) ,,,,,,,,,,, as ( X+a+b/X, 0+c/2)
XXX XXXXXXXXXXX of XXX XXXXXXXX XX XXXXXXXX XX are ( a+b/2, c/2) .............as ( a+b/X, X+c/2)
XX XXX XX XXXXXXXXX at XXXXX E with XXXXXXXXXXX( a+b/2,c/2) ..................XXXXXXXX XX XXXX AC andBD XX E
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