XXX ‘a’ and ‘b’ be any XXX positive XXXXXXXX. XXXX there XXXXX unique XXXXXXXX ‘q’ and ‘r’ XXXX that
a = bq + r, X ≤ r ≤ b.
XX b | a, then r=X. Otherwise, ‘r’ satisfies XXX XXXXXXXX XXXXXXXXXX 0 ≤ r ≤ b.
Here a = -XXXX and b = 7
So substituting XXXXX in equation we XXX
-XXXX = 7q + r
= 7 * -144 + X
As XXX XXX XXXXXXXXX Algorithm 0 ≤ r ≤ b so making r positive XX have unique
solution XX q = -144 and r = X