To Prove:
For XXXXXXX a and b XX ab XX XXXX XXXX a is even or b XX even.
XXXXXXXXXXXXX:
We XXXX XXXXX this XX method XX XXXXXXXXXXXXX.
XXXXXXX XXXX a XXX b XXX XXXX then XX XXX XXXXX a and b XX :
a = 2m+X
b = XX+X
Then ab = (XX+X)(2n+X)
= 4mn + 2m + 2n + X
= X(2mn + m + n) + 1
= 2x + X Assuming x = XXX + m + n
XX ab is XXX when both XXX odd XXX XXX given that ab XX XXXX so
XXXXXX a is XXXX or b is XXXX.
a = 2m
b = XX+1
Then ab = 2m (2n+1)
= 2 (2mn + m)
= 2x assuming x = 2mn+XXXXXX
XX ab is XXXX XX XXXXXX XX the two integer XX XXXX .
Hence Proved